Lutz, I may be repeating what has been said, but I have been thinking about what should be obvious mechanical alignment. You have said that you checked the mark on your pulley with top dead center of #1 piston. But I'm not sure that you indicated that you were sure you had the piston at top dead center of the compression stroke. I think maybe with the cylinder on the exhaust stroke the engine could be timed to run with the distributor turned really far. I may be all wrong on this. But the point I want to make is that mechanically and visually if the timing mark on the pulley is set to the right of the pointer about 1/2 inch to 3/4 of an inch and the points are turned to open just then, then the timing will be within 10 to 15 degrees give or take a smidgen of where it belongs. It could not be at 45 degrees.
First of all let me say that I made sure that when #1 piston was at TDC it also was at the end of compression stroke. Both valves were closed and the valves of zylinder #6 were overlapping.
My timing marks are set in accordance with the following table and foto:
The yellow measuring tape shows cm where 1 cm = 10 mm
Timing
[TABLE="class: cms_table"]
[TR]
[TD="class: cms_table_xl78"][/TD]
[TD="class: cms_table_xl68, colspan: 2"]
circumference pulley
[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl79"][/TD]
[TD="class: cms_table_xl73"]
mm[/TD]
[TD="class: cms_table_xl74"]
inch[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl67"]
° BTDC
[/TD]
[TD="class: cms_table_xl68"]
596[/TD]
[TD="class: cms_table_xl69"]
23.5[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl66"]1[/TD]
[TD="class: cms_table_xl83"]2[/TD]
[TD="class: cms_table_xl80"]0.1[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]5[/TD]
[TD="class: cms_table_xl84"]8[/TD]
[TD="class: cms_table_xl81"]0.3[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]10[/TD]
[TD="class: cms_table_xl84"]17[/TD]
[TD="class: cms_table_xl81"]0.7[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]15[/TD]
[TD="class: cms_table_xl84"]25[/TD]
[TD="class: cms_table_xl81"]1.0[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]20[/TD]
[TD="class: cms_table_xl84"]33[/TD]
[TD="class: cms_table_xl81"]1.3[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]25[/TD]
[TD="class: cms_table_xl84"]41[/TD]
[TD="class: cms_table_xl81"]1.6[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]30[/TD]
[TD="class: cms_table_xl84"]50[/TD]
[TD="class: cms_table_xl81"]2.0[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl70"]35[/TD]
[TD="class: cms_table_xl84"]58[/TD]
[TD="class: cms_table_xl81"]2.3[/TD]
[/TR]
[TR]
[TD="class: cms_table_xl75"]38[/TD]
[TD="class: cms_table_xl85"]63[/TD]
[TD="class: cms_table_xl82"]2.5[/TD]
[/TR]
[/TABLE]
So with my pulley which has a circumference of 23.5" the 15° position (red mark) is about 1" to the right of TDC, but like I said this is not the time #1 zylinder is fired. In my case it takes place at 45°.