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MGB the MGB cure all

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richardJr

Freshman Member
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this should aid anybody with anything dealing with any MGB repair...
Lmax ~1038 ergs/sec x (M/Ms),TBH ~ 10-7 x (M/Ms) degree K, r = m + sqr.rt.(m2 - a2), where m = GM/C2 and a = J/MC. m >= a.r = m + sqr.rt.(m2 - q2)
r = m + sqr.rt.(m2 - a2 - q2) respectively,
e = sqr. rt. (GM)or...try this if in doubt

Imax < = (G x E2 max/h x c5 x ln x 2) ..........(2)

< = (c3 x L2/4 x G x h x ln x 2) < = (L/Lpl)2 x (1/4 x ln x 2) ..........(3)Vmax = (P/h)1/2 ~ 1/t m ..........(4)P ~ (h x c6/G2 x M 2) ~ (h x c2/L2)
I think this will fix her up rather nicely!
 
hmmm... I think it equates out to: For every hour you spend restoring your 'B you can expect to spend an additional 2 more hours keeping it that way. This is, of course, assuming that you have enough energy to begin with to finish the entire resotration process. :b
 
[ QUOTE ]
this should aid anybody with anything dealing with any MGB repair...
Lmax ~1038 ergs/sec x (M/Ms),TBH ~ 10-7 x (M/Ms) degree K, r = m + sqr.rt.(m2 - a2), where m = GM/C2 and a = J/MC. m >= a.r = m + sqr.rt.(m2 - q2)
r = m + sqr.rt.(m2 - a2 - q2) respectively,
e = sqr. rt. (GM)or...try this if in doubt

Imax < = (G x E2 max/h x c5 x ln x 2) ..........(2)

< = (c3 x L2/4 x G x h x ln x 2) < = (L/Lpl)2 x (1/4 x ln x 2) ..........(3)Vmax = (P/h)1/2 ~ 1/t m ..........(4)P ~ (h x c6/G2 x M 2) ~ (h x c2/L2)
I think this will fix her up rather nicely!

[/ QUOTE ]

/ubbthreads/images/graemlins/lol.gif Oh, I get it...ha, ha, ha, ha!
 
I think I may be over thinking this... or am I not thinking hard enough? It's been a while since I've had to deal with Chemistry, Physics, and Calculus equations. But I'm seeing Temperature, voltage, energy, ... eh, does this have to do with drinking lots of beer?
 
I think it's the Lucas's Law, note that it equates to 0
 
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