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You already have the resistance of the negative battery cable and the ground strap plus the interfacial resistances of all those connections inseries with the starting current. ---Keoke
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To put this into perspective - If the total circuit resistance including battery cables, solenoid contacts, battery cable connections, & sheet metal, is only 0.015 Ohms - At 200 amps starter draw (not unusual) there will be a voltage drop of three volts at the starter. You cannot even measure 0.015 Ohms on a conventional meter.
Since it is reasonable to already have a battery drop of three to four volts due to normal internal battery resistance, this leaves only five to six volts to turn the starter. Even 0.1 Ohms extra circuit resistance would reduce the available starter voltage to zero. At high currents, even seemingly tiny resistances will markedly reduce the available starter voltage.
D
You already have the resistance of the negative battery cable and the ground strap plus the interfacial resistances of all those connections inseries with the starting current. ---Keoke
[/ QUOTE ]
To put this into perspective - If the total circuit resistance including battery cables, solenoid contacts, battery cable connections, & sheet metal, is only 0.015 Ohms - At 200 amps starter draw (not unusual) there will be a voltage drop of three volts at the starter. You cannot even measure 0.015 Ohms on a conventional meter.
Since it is reasonable to already have a battery drop of three to four volts due to normal internal battery resistance, this leaves only five to six volts to turn the starter. Even 0.1 Ohms extra circuit resistance would reduce the available starter voltage to zero. At high currents, even seemingly tiny resistances will markedly reduce the available starter voltage.
D